108. Convert Sorted Array to Binary Search Tree
Solution
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* sortedArrayToBST(vector<int>& nums) {
TreeNode* result = helper(nums, 0, nums.size() - 1);
return result;
}
TreeNode* helper(vector<int>& nums, int l, int r) {
if (l > r) {
return nullptr;
}
int mid = (l + r) / 2;
TreeNode* root = new TreeNode(nums[mid]);
root->left = helper(nums, l, mid - 1);
root->right = helper(nums, mid + 1, r);
return root;
}
};
Complexity
- Time Complexity: O(N), where N is the size of
nums
. - Space Complexity: O(N), where N is the size of
nums
.