100. Same Tree
Solution#
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if (p == nullptr && q == nullptr) {
return true;
}
if (p == nullptr || q == nullptr) {
return false;
}
if (p->val != q->val) {
return false;
} else {
return isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
}
}
};
Complexity#
- Time Complexity: O(N), where N is the number of nodes.
- Space Complexity: O(1).
All Solutions